Find an exact simplified solution to the equation on the interval 0 < x < 1.1 = 12cos(x + 1) − 5
This "equation" doesn't make sense. How is the compound inequality, "0 < x < 1.1" somehow "equal" to the expression "12 cos(x + 1) - 5"?
Find an exact simplified solution to the equation below so that 0 < θ < π.
= 0
I will guess that you mean the following:
. . . . .\(\displaystyle \dfrac{1\, +\, \tan\left(\theta\right)}{\sin\left(\theta\right)}\, =\, 0\)
You have elsewhere posted questions to "Calculus", so you've already studied trig. Just use what you learned back then:
For what angle values is the expression on the left-hand side of the equation undefined? Make a note of these.
Multiply through by the appropriate expression to clear the denominator. What equation results?
Subtract and solve the resulting trig equation, using the basic reference-angle values you memorized. Compare with the angle values you'd noted earlier, and throw out any duplicates, if any.
Find an exact simplified solution to the equation below so that 0 < θ < π/6.
1 =
tan(6θ)
I will guess that you mean the following:
. . . . .\(\displaystyle 1\, =\, \dfrac{\sqrt{3\, }}{\tan\left(6\theta\right)}\)
What did you get after you "cross-multiplied" (like you'd learned back in algebra? What are your thoughts on the resulting trig equation, especially since a basic reference-angle value (one of the ones you'd memorized back in trig) is involved in this equation?
Please be complete. Thank you!
