Finding value of c in a series: ∞∑n=0 c^(n+1)=3

[TBK1]

∞∑n=0 c^(n+1)=3, Find the exact value of c. Enter your answer as a fraction, not a decimal.

 

[BigBeachBanana]

∞∑n=0 c^(n+1)=3, Find the exact value of c. Enter your answer as a fraction, not a decimal.

\(\displaystyle \sum_{n=0}^{\infty}c^{n+1} = 3\)

It looks like a geometric series. Where are you stuck?

 

[TBK1]

I'm just not sure what i'm supposed to do to find C. I put in 2/3 because if you plug that into a/1-r it equals 3, but that was wrong.

 

[Steven G]

You're in Calculus and are having trouble with a basic algebra problem? This is not good.

I will solve a similar problem for you.

Solve (C+2)/C = -2 for C.

(C+2)/C = -2

C+2 = -2C

3C = -2

C = -2/3