I got this answer x^2 = -1 so x = sqrt of -1 which is imaginary number. The question is can I do this if x^2 = -1 I will squared both sides so x^4 = 1 then fourth root both sides so I will get x = positive or negative 1. No need for imaginaries.
It is worth noting that in the set of real numbers the \(\displaystyle \sqrt{-1}\) does not exist. As a result the equation x^2=-1 has no solution. But the real number system has a model enlargement that includes a number that solves that difficulty.I got this answer x^2 = -1 so x = sqrt of -1 which is imaginary number. The question is can I do this if x^2 = -1 I will squared both sides so x^4 = 1 then fourth root both sides so I will get x = positive or negative 1. No need for imaginaries.
... the equation x^2=-1 has no solution.
Because the domain of definition was the real number set, the statement was correct.Correction. The equation has no Real solutions.