Kashlanoue
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- Jul 3, 2020
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Hi! How would I find all values that satisfy the equation
A^2=(B^2+C^2)/2
Where all values must be whole numbers
A^2=(B^2+C^2)/2
Where all values must be whole numbers
Finding values that satiate this equation
- Thread starter Kashlanoue
- Start date
Cubist
Senior Member
- Joined
- Oct 29, 2019
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- 1,699
I want to give you clues without giving the full answer, but these are probably quite obvious.
There's a trivial set of solutions if you consider A=m, B=m, C=?
And there are more solutions too. If you know that Pythagorean triples can be generated then consider the result of \((x+y)^2 + (x-y)^2\)
There's a trivial set of solutions if you consider A=m, B=m, C=?
And there are more solutions too. If you know that Pythagorean triples can be generated then consider the result of \((x+y)^2 + (x-y)^2\)
3 4 5 <-> 1 7 5
6 8 10 <-> 2 14 10
5 12 13 <-> 7 17 13
6 8 10 <-> 2 14 10
5 12 13 <-> 7 17 13