M meshun01 New member Joined Feb 11, 2006 Messages 11 Mar 9, 2006 #1 6.) y=3x^4 - 2x^2 Find y' Which one way is correct? y'= 12x^3 - 4x or y= 12x^3 * (-2x^2) + (-4x)*(3x^4)
6.) y=3x^4 - 2x^2 Find y' Which one way is correct? y'= 12x^3 - 4x or y= 12x^3 * (-2x^2) + (-4x)*(3x^4)
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Mar 10, 2006 #2 d(ax^b)=abx^(b-1) so y'= 12x^3 - 4x is correct.
