We can correct your mistake only if you share your work - otherwise we would have to throw stones in dark!I know that the derivative of 1 is obviously 0, but using the first principles definition of the derivative limit rules for a constant, it is 1. Where am I going wrong here? Thanks.
Did you even read the question? It says the derivative of 1. That is \(f(x)=1\).Isn't it that if f(x) = C, then lim x-> n = C? Then substitute C=1.
The first derivative rule for a constant isI know that the derivative of 1 is obviously 0, but using the first principles definition of the derivative limit rules for a constant, it is 1. Where am I going wrong here? Thanks.
We can tell where you are going wrong when you don't show what you did!I know that the derivative of 1 is obviously 0, but using the first principles definition of the derivative limit rules for a constant, it is 1. Where am I going wrong here? Thanks.
The limit of WHAT "as z=x->n? And what is "n"? Where did that come from? It is true that \(\displaystyle \lim_{x\to x_0} f(x)= f(x_0)= C\) where \(\displaystyle x_0\) is any value of C. That says that f(x)= C is continuous. It says nothing about the derivative!Isn't it that if f(x) = C, then lim x-> n = C?
Then substitute C=1.