Formula

[jshaziza]

N=(k^2-3k)/2
solve for k.

Could someone show me at least one or two of the first steps in solving this. Thx.

 

[Mrspi]

N=(k^2-3k)/2
solve for k.

Could someone show me at least one or two of the first steps in solving this. Thx.

Multiply both sides by 2:

2N = k<SUP>2</SUP> - 3k

Subtract 2N from both sides of the equation:

0 = k<SUP>2</SUP> - 3k - 2N

Now....use the quadratic formula to solve the equation for k in terms of N.....

a = 1
b = -3
c = -2N