You are given some operation that gives that data and are asked to find how the operation would be applied to the final data. There are infinitely many perfectly valid answers!
One method is to treat this as values given by a function of two variables, z= f(x,y).
Then we are given that f(59, 21)= 6146, f(83, 61)= 9351, and f(77, 42)= 8633.
Given any n data points, there always exist a polynomial of degree n-1 that gives those n data points: two points determine a line, three points determine a parabola, etc. Since we have three data points, I would look for a function of the form \(\displaystyle f(x,y)= ax^2+ bxy+ cy^2\). We have three equations to solve for a, b, and c.
\(\displaystyle 59^2a+ (59)(21)b+ 21^2c= 6246\)
\(\displaystyle 83^2a+ (83)(61)b+ 61^2c= 9351\)
\(\displaystyle 77^2a+ (77)(42)b+ 42^2c= 8633\)
To answer the question, solve those three linear equations for a, b, and c then set x= 92, b= 62 in \(\displaystyle ax^2+ bxy+ cy^2\).
I don't say that is THE answer you are looking for but it certainly is one valid answer.