Events A and B are such that P(A or B) = 0.8, P(A) = 0.5 and P(A given B) = 0.25. Find P(A and B')
This is what I tried:
Knowing that
P(A and B) = P(A) + P(B) - P(A or B)
and knowing that
P(A given B) = P(A and B) ÷ P(B)
I subbed in P(A), P(A or B) and P(A given B) to their respective formulas:
P(A and B) = 0.5 + P(B) - 0.8
0.25 = P(A and B) ÷ P(B)
Embedding P(A and B) into the second formula:
0.25 = (0.5 + P(B) - 0.8) ÷ P(B)
Unfortunatly P(B) turns out to be a negative probability, but I need it to find out what P(A and B') is!
I would very much appreciate someone's help on this as I really want to understand probability for FSMQ.
This is what I tried:
Knowing that
P(A and B) = P(A) + P(B) - P(A or B)
and knowing that
P(A given B) = P(A and B) ÷ P(B)
I subbed in P(A), P(A or B) and P(A given B) to their respective formulas:
P(A and B) = 0.5 + P(B) - 0.8
0.25 = P(A and B) ÷ P(B)
Embedding P(A and B) into the second formula:
0.25 = (0.5 + P(B) - 0.8) ÷ P(B)
Unfortunatly P(B) turns out to be a negative probability, but I need it to find out what P(A and B') is!
I would very much appreciate someone's help on this as I really want to understand probability for FSMQ.