arthur ohlsten said:... Please check my algebra ... There are some missing grouping symbols, Arthur; otherwise, it looks good.
2 = 2/[x - 4] + 3/[x + 1]
place over common denominator [x - 4][x + 1]
2 = {2[x + 1] + 3[x - 4]}/{[x - 4][x + 1]}
2[x - 4][x + 1] = 2x + 2 + 3x - 12
2[x^2 - 3x - 4] = 5x - 10
2x^2 - 6x - 8 = 5x - 10
2x^2 - 11x + 2 = 0
x = 11 +/- [121 - 16]^(1/2) all over 4
x = 11 +/- (105)^(1/2) all over 4
x = 11/4 + ?105/4
x = 11/4 - ?105/4
x ? 5.31 or x ? .19
arthur ohlsten said:Your algebra is correct This is an unreferenced pronoun, Arthur. Are you talking to yourself?
Arthur