Function need help tho
- Thread starter Zetrics
- Start date
D
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You are going in the right direction.
Use the given definition of h(x): \(\displaystyle \ \to \ \) h(x) = p * x + q
h[(x-1)^2] = p * (x-1)^2 + q
and continue......
Dr.Peterson
Elite Member
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- Nov 12, 2017
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- 16,087
In your work, you dropped the "+ 5" in g, and have not yet applied the definition of h.