Function with complex numbers

AM87

New member
Joined
May 14, 2019
Messages
2
Hi,

I'm trying to graph a function that contains imaginary numbers. I may have made a mistake in calculating the modulus of the denominator (step 2 to step 3), or it may be right. Either way, I'm not sure how to get rid of the imaginary numbers, or if they can't be rid of, how to graph the function. I'm trying to use Excel, which I
understand isn't the best program but it's what I've got to work with. Any help would be appreciated. Thanks!

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Jomo

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Dec 30, 2014
Messages
3,772
Line 3 from line 2: I am assuming that you mean cos(p3H) and not cos(p3)*H. Am I right??
\(\displaystyle A+B \neq \sqrt{A^2+B^2}\)
For example \(\displaystyle 7 = 3+4\neq\sqrt{3^2+4^2}=\sqrt{9+16}= \sqrt{25} = 5\)

Now (a+bi)(a-bi) = a2+ b2. Use this to get the denominator to be real.
 
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AM87

New member
Joined
May 14, 2019
Messages
2
Line 3 from line 2: I am assuming that you mean cos(p3H) and not cos(p3)*H. Am I right??
\(\displaystyle A+B \neq \sqrt{A^2+B^2}\)
For example \(\displaystyle 7 = 3+4\neq\sqrt{3^2+4^2}=\sqrt{9+16}= \sqrt{25} = 5\)

Now (a+bi)(a-bi) = a2+ b2. Use this to get the denominator to be real.
Yes, what you assumed is right, with cos (PsH). I used the square root of the sum of the squares because those | | I believe are the 'modulus' of what's in the denominator.

| x + iy | = sqrt(x^2 + y^2)

That was my thought process.
 
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