How would you go about doing part c? As you can see from the working out, my range for a is defiantly wrong and I don’t know how else to go about it?
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Is the answer a>2 and a<2?(2x+3)/x is NOT 3. 2x/x is NOT 0, and even if it was 0, you still need to divide the 3 by x!
(2x+3)/x = (2x/x) + (3/x) = 2 + 3/x.
Think about what is required for the line y=ax (a line that crosses the origin) to cross the function in exactly one place. Do not use algebra, but rather think how this can be done. Draw lines and figure out the requirement for the slope.
Maybe? Can you explain why? Did you miss one other a value?Is the answer a>2 and a<2?
I used desmos to see where the lines would cross. But it is to do with how steep the gradients are. But I don’t think there is another one because it seems to cross both lines otherwiseMaybe? Can you explain why? Did you miss one other a value?
No, a>2 and a<2 is not part of the answer. Find the slope of each line, and then see which lines through the origin will cross just one of the two lines. Then there is one more line.Is the answer a>2 and a<2?