guardgirl08
New member
- Joined
- Jun 14, 2011
- Messages
- 13
I want to apologize up front if I do not write the question the right way for you.
Question: Given the functions g(x)= square root of x+7 and h(x)= 1/(2x-3) find g(h(x)) and h(g(x)).
I have already found the first one. The second one is confusing me.
So far I have h(g(x))= 1/(2square root of x+7) -3 *the minus 3 is in the denominator next to the square root*
I am not sure if I can take it any further?
Question: Given the functions g(x)= square root of x+7 and h(x)= 1/(2x-3) find g(h(x)) and h(g(x)).
I have already found the first one. The second one is confusing me.
So far I have h(g(x))= 1/(2square root of x+7) -3 *the minus 3 is in the denominator next to the square root*
I am not sure if I can take it any further?