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geomerty but algerbra ???
- Thread starter rhslaxer
- Start date
If those are the sides of triangle RST, then not enough info is given.rhslaxer said:A-If RS=3x+1, ST=2x-2, and RT=64, find the value of x.
B-Find RS and ST.
Unless "greater than" is expected:
3x+1 + 2x-2 > 64
5x > 65
x > 13
If you can't follow that, only your teacher can help...
Hello, rhslaxer!
You suspected that it involved Geomtry.
Why didn't you make a sketch?
\(\displaystyle \text{I suspect that the points }R,S,T\text{ are collinear.}\)
\(\displaystyle \text{We see that: }\;RS + ST \;=\;RT\)
\(\displaystyle \text{So we have: }\;(3x+1) + (2x-2) \:=\:64 \quad\Rightarrow\quad 5x - 1 \:=\:64 \quad\Rightarrow\quad 5x \:=\:65\)
\(\displaystyle \text{(a) Therefore: }\:x \:=\:13\)
\(\displaystyle \text{(b) }\;\begin{Bmatrix}RS &=& 3x+1 &=& 3(13)+1 &=& 40 \\ \\[-3mm] ST &=& 2x-2 &=& 2(13)-2 &=& 24 \end{Bmatrix}\)
You suspected that it involved Geomtry.
Why didn't you make a sketch?
\(\displaystyle \text{If }RS\,=\,3x+1,\; ST\,=\,2x-2,\;RT\,=\,64,\)
. . \(\displaystyle \text{(A) Find the value of }x\)
.
. . \(\displaystyle \text{(B) Find }RS\text{ and }ST.\)
\(\displaystyle \text{I suspect that the points }R,S,T\text{ are collinear.}\)
Code:
3x+1 S 2x-2
R *-----------*-----------* T
: - - - - - 64 - - - - :\(\displaystyle \text{So we have: }\;(3x+1) + (2x-2) \:=\:64 \quad\Rightarrow\quad 5x - 1 \:=\:64 \quad\Rightarrow\quad 5x \:=\:65\)
\(\displaystyle \text{(a) Therefore: }\:x \:=\:13\)
\(\displaystyle \text{(b) }\;\begin{Bmatrix}RS &=& 3x+1 &=& 3(13)+1 &=& 40 \\ \\[-3mm] ST &=& 2x-2 &=& 2(13)-2 &=& 24 \end{Bmatrix}\)