Geometric sequence

Ashiya

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If m-1, m+3 and m+12 are consecutive terms in a geometric sequence, determine the values of the three terms for all such sequences??
 
Ashiya said:
If m-1, m+3 and m+12 are consecutive terms in a geometric sequence, determine the values of the three terms for all such sequences??

Consecutive terms in a geometric series looks like ar[sup:3kuu13v4]n[/sup:3kuu13v4]. ar[sup:3kuu13v4]n+1[/sup:3kuu13v4] and ar[sup:3kuu13v4]n+2[/sup:3kuu13v4]

then

r=arn+1arn=m+3m1.............................(1)\displaystyle r \, = \frac{ar^{n+1}}{ar^n} \, = \, \frac{{m+3}}{m-1} .............................(1)

and

r=arn+2arn+1=m+12m+3.............................(2)\displaystyle r \, = \frac{ar^{n+2}}{ar^{n+1}} \, = \, \frac{{m+12}}{m+3} .............................(2)

Equating (1) and (2)

(m+3)2=(m1)(m+12)\displaystyle (m+3)^2 \, = \, (m-1)\cdot (m+12)

solve the equation above to find 'm'.
 
Let a=m-1 , b=m+3 ,c=m+12.
Since they are 3 concequtive numbers,and its a Geometric sequence:So,
b/a=c/b ---------- Solve for m and then substitute .

Right Mr Khan,?
 
Aladdin said:
Let a=m-1 , b=m+3 ,c=m+12.
Since they are 3 concequtive numbers,and its a Geometric sequence:So,
b/a=c/b ---------- Solve for m and then substitute .

Right Mr Khan,?
Yes, you have correctly restated what the tutor had posted.
 
Re:

stapel said:
Aladdin said:
Let a=m-1 , b=m+3 ,c=m+12.
Since they are 3 concequtive numbers,and its a Geometric sequence:So,
b/a=c/b ---------- Solve for m and then substitute .

Right Mr Khan,?
Yes, you have correctly restated what the tutor had posted.
That means Correct :wink: .
 
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