Prove that any angle bisector of a triangle separates the opposite sides into segmants whose lengths have the same ratio as the ratio of the lengths of the remaining two sides. (Hint: In triangle ABC, let AD be the angle bisector of angle A. What we want to show is that CD/BD = AC/AB. To start, find point E on AB so that DE is parallel to AC.)
geometry - help study for final (angle bisector, ratios)
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