Hello, I can't seem to solve the following problem:
On the side AB of a triangle ABC (with angles A = α, B = β [FONT="]and height AH perpendicular to BC, BC = a) there is a point K such that AK:BK = 1:2. A circle drawn through point K is tangent to the side BC at point H. Find the radius of this circle.
Using the law of sines we can quickly find that AH = a*sin([/FONT]α+β)*sinβ/sinα. However, I appear to be stuck at this point of the solution.
Any help is greatly appreciated.
On the side AB of a triangle ABC (with angles A = α, B = β [FONT="]and height AH perpendicular to BC, BC = a) there is a point K such that AK:BK = 1:2. A circle drawn through point K is tangent to the side BC at point H. Find the radius of this circle.
Using the law of sines we can quickly find that AH = a*sin([/FONT]α+β)*sinβ/sinα. However, I appear to be stuck at this point of the solution.
Any help is greatly appreciated.