J josh90 New member Joined Aug 10, 2006 Messages 10 Aug 13, 2006 #1 Hey, I have a geometry question: The diagonals of square PQRS interesect at T. If PT = 2x + 6 and QS = 6x - 10, find the length of PR. Would I do "2x + 6+x = 6x - 10"? If anyone can help that would be great. Thx.
Hey, I have a geometry question: The diagonals of square PQRS interesect at T. If PT = 2x + 6 and QS = 6x - 10, find the length of PR. Would I do "2x + 6+x = 6x - 10"? If anyone can help that would be great. Thx.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Aug 13, 2006 #2 In a square the diagonals bisect each other and are congruent. Hence, length of QS is twice the length PT.
In a square the diagonals bisect each other and are congruent. Hence, length of QS is twice the length PT.
