amathproblemthatneedsolve
Junior Member
- Joined
- May 12, 2019
- Messages
- 189
The distance from the centre of the hole to the edge AC where the triangle ABC joins the square needs to be at least 2 centimetres. Assume that the center of the hole is on the median from B to AC. How much closer towards the edge AC could the hole be drilled? Justify your answer.
Use the following information in your investigation. The vertices of the triangle are A (4, −2), B (1, 9) and C (10, 2). The points D (14, −4) and E (8, –8) are the other vertices of the quadrilateral ACDE. The line 2y = −3x + 21 is an axis of symmetry of the total shape ABCDE. The scale of the diagram is 1 unit = 1 cm.
centre of the hole is at (5,3) I've found the distance from Centre hole (5,3) to (7,0)Ac to be √13
Use the following information in your investigation. The vertices of the triangle are A (4, −2), B (1, 9) and C (10, 2). The points D (14, −4) and E (8, –8) are the other vertices of the quadrilateral ACDE. The line 2y = −3x + 21 is an axis of symmetry of the total shape ABCDE. The scale of the diagram is 1 unit = 1 cm.
centre of the hole is at (5,3) I've found the distance from Centre hole (5,3) to (7,0)Ac to be √13