Given that u_k > 0 and u_{k+1} < 0, find the value of sum [n=1 to k] u_n

petr

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Hello,

I ve got a problem to solve a problem 8.C)

http://filestore.aqa.org.uk/subjects/AQA-MPC2-QP-JUN14.PDF

here is the solution
http://filestore.aqa.org.uk/subjects/AQA-MPC2-W-MS-JUN14.PDF

the problem is the value of n. I construct the inequalities but after i have got two value and i dont know what to pick 31.75 and 30.75. In the solution papers there is n value 31 and i have no idea how they come up with it. Could anybody explain, please.

They just write 31.75 =>31 and 30.75=>31 and I just dont get it.

Thank you for help.
 
For other viewers, the exercise and solution are as follows:



8 . . . . .An arithmetic series has first term a and common difference d.

. . . . . ..The sum of the first five terms of the series is 575.

. .(a). . .Show that a + 2d = 115.

. .(b). . .Given that the tenth term of the series is 87, find the value of d.

. .(c). . .The n-th term of the series is un. Given that uk > 0 and uk+1 < 0, find the value of:

. . . . . . . . . .\(\displaystyle \displaystyle \sum_{n\, =\, 1}^k \, u_n\)



8(a). . .\(\displaystyle S_5\, =\, \dfrac{5}{2}\, \bigg[\, 2a\, +\, (5\, -\, 1)d\, \bigg]\)

. . . . . .\(\displaystyle \dfrac{5}{2}\, \bigg[\, 2a\, +\, (5\, -\, 1)d\, \bigg]\, =\, 575;\, \mbox{ }\, 5\, (2a\, +\, 4d)\, =\, 575\, \times\, 2\)

. . . . . .\(\displaystyle 2a\, +\, 4d\, =\, 115\, \times\, 2\, \Rightarrow\, a\, +\, 2d\, =\, 115\)

8(b). . .\(\displaystyle a\, +\, (10\, -\, 1)d\, =\, 87\)

. . . . . .\(\displaystyle a\, +\, 2d\, =\, 115,\, a\, +\, 9d\, =\, 87\, \Rightarrow\, 7d\, =\, 87\, -\, 115\)

. . . . . .\(\displaystyle 7d\, =\, -28,\, d\, =\, -4\)

8(c). . .\(\displaystyle \mbox{When }\, d\, =\, -4,\, a\, =\, 123.\)

. . . . . .\(\displaystyle u_k\, =\, 123\, +\, (k\, -\, 1)(-4)\, >\, 0\)

. . . . . .\(\displaystyle u_{k+1}\, =\, 123\, +\, (k)(-4)\, <\, 0\)

. . . . . .\(\displaystyle k\, <\, 31.75,\, k\, >\, 30.75\, \Rightarrow\, k\, =\, 31\)

. . . . . .\(\displaystyle \displaystyle \sum_{n\, =\, 1}^{k}\, u_n\, =\, \dfrac{31}{2}\, \bigg[\, 2a\, +\, (31\, -\, 1)d\, \bigg]\, =\, 1953\)



I've got a problem to solve a problem 8.C)

the problem is the value of n.
No; the issue is finding the value of k, not n.

I construct the inequalities but after i have got two value and i dont know what to pick 31.75 and 30.75.
What do you mean by "what to pick"? You were given two inequalities, you solved the two inequalities, and thus arrived at bounds on the value of k , which is the value you need to find. Where is the issue?

In the solution papers there is n value 31
No; they have k = 31 , because k is bounded by the in equalities you say you solved: 30.75 < k < 31.75 , k a whole number.

and i have no idea how they come up with it. Could anybody explain, please.

They just write 31.75 =>31 and 30.75=>31 and I just dont get it.
No, they don't. They show that k, a whole number, is less than 31.75 and greater than 30.75. What who le number is between 30.75 and 31.75?

As for how they got 31.75 and 30.75, what did you get when you solved the two given inequalities?

Please show all of your steps. Thank you! ;)
 
whole number

Thank you for this amazing answer but how do you know they want whole number?

hence it can be any of the values between 30.75 and 31.75.
 
Thank you for this amazing answer but how do you know they want whole number?
hence it can be any of the values between 30.75 and 31.75.
In the notation \(\displaystyle \sum\limits_{k = J}^N {{u_k}} \) it is understood that \(\displaystyle J\) is an integer and \(\displaystyle N\ge J\) is also an integer.
In other words, sequences are indexed by using integers. The sum uses all terms from \(\displaystyle u_J\) to \(\displaystyle u_N\).
 
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