M mohka921 New member Joined Sep 24, 2005 Messages 1 Sep 24, 2005 #1 I am really not getting finding the perfect square for two problems; 1. w^2-5w 2. 2m^2-m-15=0 Please explain the steps in solving these particular problems Thanks
I am really not getting finding the perfect square for two problems; 1. w^2-5w 2. 2m^2-m-15=0 Please explain the steps in solving these particular problems Thanks
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Sep 24, 2005 #2 It should say = 0. You simply add the square of 1/2 the multiplier of the w term w^2-5w = 0 w^2-5w+(25/4)=25/4 (w-5/2)^2=25/4 For the second, divide by 2 first to get 1 for the multiplier m^2
It should say = 0. You simply add the square of 1/2 the multiplier of the w term w^2-5w = 0 w^2-5w+(25/4)=25/4 (w-5/2)^2=25/4 For the second, divide by 2 first to get 1 for the multiplier m^2
