Graphing a Tan Function

[mmm4444bot]

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$\displaystyle 0 = \tan x$

$\displaystyle 0 = \tan (1) x$ - Note $\displaystyle 1 * x = x$

$\displaystyle 0 = \tan x$

tan(x) is a number.

If you write tan(1), that means x=1, and you're taking the tangent of 1 radian, which is about 1.5574 (rounded to four places).

If you write tan(1)x, that means the number 1.5574 times the number x.

Why are you writing tan(1)x ?

Did you tell us that 1*x = x because you're suggesting that tan(1)x somehow means tan[(1)(x)]?

I'm trying to understand why you told us that 1 times x is x...that kinda goes without saying, does it not?

 

[mmm4444bot]

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Find Two More Points to Make an Accurate Graph

The positive and negative versions of $\displaystyle A$ correspond to the y coordinates of the new points.

$\displaystyle A = 1$ So our two $\displaystyle y$ coordinates are $\displaystyle -1$ and $\displaystyle 1$

I don't follow your reasoning on the relationship between A=1 and the y-coordinate of "two more points" on the graph of tan(x). Can you elaborate on what you're thinking?

 

[mmm4444bot]

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Connect the [three] Points

Now you have your graph

For somebody who is unfamiliar with the tangent function's behavior, I don't think that 3 points are sufficient to obtain a good graph.

My instructions for plotting tan(x) from scratch would be to build a table of x,y values -- using a calculator to evaluate tan(x) for several values of x within the interval.

Will you please clarify the purpose of your project?

 

[Deleted member 4993]

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The two asymptotes are $\displaystyle -\dfrac{\pi}{2}$ and $\displaystyle \dfrac{\pi}{2}$

Find the x intercept

$\displaystyle 0 = \tan x$ ........................................ (1)

$\displaystyle 0 = \tan (1) x$ - Note $\displaystyle 1 * x = x$ ... By convention, tan(1)x = [ tan(1) ] * x ..... perhaps you meant to write tan[(1)x]

$\displaystyle 0 = \tan x$ .... you are repeating line (1)..... what was the purpose of line above! you could have (and should have) started from here.

$\displaystyle \arctan(0) = 0$

The $\displaystyle x$ intercept $\displaystyle = 0$


Find Two More Points to Make an Accurate Graph

Three points are not sufficient for any curve - other than a straight line. While drawing a polynomial - you should plot at least two more point than the degree of the polynomial (3 pts for linear, 4 points for parabolic, 5 points for cubic, etc. You have transcendental function - infinite series - you need (in my opinion) at least five points . [/QUOTE].

 

[Jason76]

As pointed out in another thread, didn't take both sides when doing the $\displaystyle \arctan$ thing. So will update all posts soon.