graphing coordinates

confusedstudent

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Apr 30, 2008
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i am having trouble with my math homework. its says....

Graph each system of equations using the coordinate plane provided. Then determine whether the system has one solution, no solution, or infinitely many solutions. If hte system has one solution, name it.

y=3x and y+x-4=0


any help?
 

wjm11

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Nov 13, 2004
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Graph each system of equations using the coordinate plane provided. Then determine whether the system has one solution, no solution, or infinitely many solutions. If hte system has one solution, name it.

y=3x and y+x-4=0
What work have you done? What have you tried? What did you see when you graphed these equations?

Both equations will graph as lines. If the lines are not parallel (and these are not), they will cross at some point. That intersection is the solution to the system. In other words, the x and y values of the intersection point are the x and y that will work in both equations.
 

masters

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Mar 30, 2007
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Sometimes, when you are trying to manually solve systems of linear equations graphically, it is difficult to see exactly where the intersection is (unless the coordinates happen to be integers).

So, to be sure, once you have graphed them and determined they do intersect, take your best guess about what that intersection is (use graph paper and a straight-edge).

Then check your solution algebraically.

Step 1: Set both linear equations to y = mx + b. "m" is the slope and "b" is the y-intercept

y = 3x
y = -x + 4

Inspect the slopes: 3 and -1
They are different , so the lines do, in fact, intersect.

Set 3x = -x + 4, and solve for x.
Use either equation to substitute x to find y. Now you have your point of intersection (x, y).

Just to review:
If the slopes were equal but the y-intercepts were different, the lines would've been parallel (no solution).
If the slopes and y-intercepts were equal, the lines would've coincided (infinite number of solutions)
 
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