Graphing Functions -Finding Asymptotes & Intercepts

vajujy

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Oct 9, 2007
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I have this problem that I cant finish, it says:

Graph f(x)= (-4)/(x^2+1), find the asymptotes and intercepts.

I found the asymptotes and I graphed the functions already, but I dont know how to find the x and y intercepts. Can someone please help me?? Thanks
 
Isn't is clear that (0,-4) is the y-intercept?
Is it possible for y to equal zero?
 
Well my problem is that I dont know how you determine what the intercepts are. Thanks though.
 
vajujy said:
I have this problem that I cant finish, it says:

Graph f(x)= (-4)/(x^2+1), find the asymptotes and intercepts.

I found the asymptotes and I graphed the functions already, but I dont know how to find the x and y intercepts. Can someone please help me?? Thanks
Definition of intercepts:

x-intercepts - The value of x's at which f(x) = 0 (The graph crosses the x-axis)

y-intercept - The value of 'y' at which x = 0 (The graph crosses the y-axis)

Suppose you have:

y = x^2 - 5x + 6

then for x-intercept

y = 0 = (x-3)(x-2)

The x intercept points are then (2,0) and (3,0)

for y-intercept

y = 0^2 - 5*0 +6

Hence the y-intercept point is (0,6)
 
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