\(\displaystyle x+y>2\)

\(\displaystyle y>2-x\)

Since y is always on the vertical axis,

unless you're like me and "cheat" when graphing inverses,

then the region above the line

\(\displaystyle y=2-x\)

contains all values of \(\displaystyle y>2-x\)

since y=2-x on the line, y<2-x below the line and y>2-x above the line.

\(\displaystyle 3x-2y<k\)

\(\displaystyle 3x<2y+k\)

\(\displaystyle 3x-k<2y\)

\(\displaystyle y>\frac{3}{2}x-\frac{k}{2}\)

Same story, just fill in the blank for k.

The equations you specified are "linear", straight lines.

Hence the inequalities are relatively easy.

I also recommend you do what Mark asked,

otherwise I messed up his post.