- Thread starter cougar77d
- Start date

Are you graphing those individually? Easiest way would be to find the x-intercept (by solving for x when y = 0) and the y-intercept (by solving for y when x = 0) and connect them with a line, extending both ways.

-4(20) + 5y = 0

-80 + 5y = 0

etc. etc.

Usually, you use smaller x values so that your axes are easier to deal with. So maybe x = 5?

Also, if you really want you could put it into the y = mx + b form.

-4x + 5y = 0

5y = -4x

y = -4x/5

Same result either way.