Graphing problem

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Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite lenght?

a)X^4>=1

b)X^3<=27

c)X^2>=16

d)2<=|X|<=5

e)2<=3X+4<=6


The last two inequalities look the same to me! I cannot tell what the answer is when I graph them! please give me some help :p
 
Hello, Alejandra9!

Which of the following inequalities has a solution set that, when graphed on the number line,
is a single line segment of finite length?

\(\displaystyle a)\:x^4\,\geq\,1\;\;\;b)\:x^3\,\leq\,27\;\;\;c)\;x^2\,\geq\,16\;\;\;d)\;2\,\leq\,|x|\,\leq\,5\;\;\;e)\;2\,\;\leq\,3x\,+\,4\,\leq\,6\)
. .
\(\displaystyle a)\;x^4\,\geq\,1\;\;\Rightarrow\;\;x^2\,\geq\,1\;\;\Rightarrow\;\;|x|\,\geq\,1\;\;\Rightarrow\;\;x\,\leq -1\,\) or \(\displaystyle \,x\,\geq\,1\)

. . . = = = = \(\displaystyle \bullet\) - - - - - \(\displaystyle \bullet\) = = = =
. . . . . . . . . -1. . . . . . 1


\(\displaystyle b)\;x^3\,\leq\,27\;\;\Rightarrow\;\;x\,\leq\,3\)

. . . = = = = = = = = \(\displaystyle \bullet\) - - - - -
. . . . . . . . . . . . . . . . 3


\(\displaystyle c)\;x^2\,\geq\,16\;\;\Rightarrow\;\;|x|\,\geq\,4\;\;\Rightarrow\;\;x\,\leq -4\,\) or \(\displaystyle \,x\,\geq\,4\)

. . . = = = \(\displaystyle \bullet\) - - - - - \(\displaystyle \bullet\) = = =
. . . . . . . .-4. . . . . .4


\(\displaystyle d)\;2\,\leq\,|x|\,\leq\,5\)

This has two statements: \(\displaystyle \:x\,\leq\,-2\,\) or \(\displaystyle \,x\,\geq\,2\)
. . . . . . . . . . . . . . . . .and: -\(\displaystyle 5\,\leq\,x\,\leq 5\)

. . . - - \(\displaystyle \bullet\) = = \(\displaystyle \bullet\) - - - \(\displaystyle \bullet\) = = \(\displaystyle \bullet\) - - -
. . . . .-5 . . . -2 . . . 2 . . . .5


\(\displaystyle e)\;2\:\leq\:3x\,+\,4\:\leq\:6\)

Solve for \(\displaystyle x\).

Subtract 4: \(\displaystyle \;-2\:\leq\:3x\:\leq\:2\)

Divivde by 3: \(\displaystyle \;-\frac{2}{3}\:\leq\:x\;\leq\:\frac{2}{3}\)

. . . - - - \(\displaystyle \bullet\) = = = = = \(\displaystyle \bullet\) - - -
. . . . . . -\(\displaystyle \frac{2}{3}\) . . . . . . . . \(\displaystyle \frac{2}{3}\;\;\;\;\;\) <----- This one!
 
thank you so much!

Thank you so much for all the help Soroban! :p
 
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