graphing the center and radius of a circle

sbsbsbsbsb

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Mar 9, 2010
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Ok the instructions are to sketch the graph of (x-2)^2 + (y-5)^2 < 9
the center is 2, 5 but is the radius 9 or 3?
 
\(\displaystyle Here \ is \ the \ graph \ of \ (y-5)^2+(x-2)^2 \ = \ 9\)

\(\displaystyle Now, \ what \ do \ you \ have \ to \ do \ to \ the \ said \ graph \ to \ have \ (y-5)^2+(x-2)^2 \ \le \ 9?\)

[attachment=0:e52tj3fd]zab.jpg[/attachment:e52tj3fd]
 

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you have to shade the inside of the circle since all the points in the circle can work right?
 
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