dy/dt+5*y;y(0)=1
S srmichael Full Member Joined Oct 25, 2011 Messages 848 Feb 9, 2012 #2 mmm309 said: dy/dt+5*y;y(0)=1 Click to expand... You sure it's not \(\displaystyle \displaystyle \frac{dy}{dt}=5y\)??
mmm309 said: dy/dt+5*y;y(0)=1 Click to expand... You sure it's not \(\displaystyle \displaystyle \frac{dy}{dt}=5y\)??
M mmm309 New member Joined Feb 9, 2012 Messages 2 Feb 9, 2012 #3 My Bad. Equation should read dy/dt+5*y=0; y(0)=1
S srmichael Full Member Joined Oct 25, 2011 Messages 848 Feb 9, 2012 #4 mmm309 said: My Bad. Equation should read dy/dt+5*y=0; y(0)=1 Click to expand... Do you remember how to separate the variables and then integrate? \(\displaystyle \displaystyle \frac{dy}{dt}+5y=0\) \(\displaystyle \displaystyle \frac{dy}{dt}=-5y\) \(\displaystyle \displaystyle \frac{dy}{y}=-5dt\) Now integrate both sides and let us know if you get stuck.
mmm309 said: My Bad. Equation should read dy/dt+5*y=0; y(0)=1 Click to expand... Do you remember how to separate the variables and then integrate? \(\displaystyle \displaystyle \frac{dy}{dt}+5y=0\) \(\displaystyle \displaystyle \frac{dy}{dt}=-5y\) \(\displaystyle \displaystyle \frac{dy}{y}=-5dt\) Now integrate both sides and let us know if you get stuck.
A afrazer721 New member Joined Feb 1, 2012 Messages 26 Feb 11, 2012 #5 mmm309 said: dy/dt+5*y;y(0)=1 Click to expand... Originally Posted by mmm309 My Bad. Equation should read dy/dt+5*y=0; y(0)=1 Do you remember how to separate the variables and then integrate? lny=-5t e^lny=e^-5t y=e^-5t y(0)=e^-5(0) y(0)=1. Last edited: Feb 11, 2012
mmm309 said: dy/dt+5*y;y(0)=1 Click to expand... Originally Posted by mmm309 My Bad. Equation should read dy/dt+5*y=0; y(0)=1 Do you remember how to separate the variables and then integrate? lny=-5t e^lny=e^-5t y=e^-5t y(0)=e^-5(0) y(0)=1.