Do you know how to factor numbers? The second one (since you say you have already done the first) is \(\displaystyle x^2- 38x- 80\). To "factor" a trinomial means to find integers, a and b, so that the trinomial is equal to the product \(\displaystyle (x- a)(x+ b)= x^2- x+ bx- ab= x^2- (a- b)- ab\) (I have used the same negative signs as in the given polynomial). So how does 80 factor? Since 80 is an even number, "2" is a factor- the easiest way to factor 80 is 2 times 40 and it just happens that 40- 2= 38! So this factors as (x- 2)(x+ 40).
For the "rectangle" problem, I presume you know, from elementary geometry, that "area equal length times width". Here, you are told that the area is given by \(\displaystyle x^2+ 16x- 36\) and that the width is x- 2. So the length must be some number "a" such that \(\displaystyle (x+ a)(x- 2)= x^2+ 16x- 36\) (I know it must be "-a" rather than "+a" because (+a)(-2) will be negative as is -36. In fact since -2a must equal -36, a must equal -36/-2. So what is a?