This is clearly a problem involving algebraic equation.Please help me solve the exercise:
Find the error in the following argument, sqrt(x^2+1)=x+1 and so let x=2 sqrt(5)=9, therefore 5=9
Thanks in advance!!!
As you've presented it, the exercise is to locate mistake(s) in somebody else's work.Please help me solve the exercise
Above, I have highlighted (in red) an error. Focus on that, to start. Once you tell us the correct value, we can discuss the exercise further. :cool:Find the error in the following argument,
sqrt(x^2+1) = x+1
and so let x = 2
sqrt(5) = 9,
therefore 5 = 9
It looks as though you are assuming that sqrt[x^2 + 1] is everywhere (that is, for all values of x) equal to x + 1. Why? You know that (x + 1)^2 is not equal to x^1 + 1 (since powers don't "distribute"), so why are you assuming that the wrong statement "works" "going backwards"?Find the error in the following argument, sqrt(x^2+1)=x+1 and so let x=2 sqrt(5)=9, therefore 5=9
1st of all sqrt(5) is not 5, so even if sqrt(5) = 9 it does NOT follow that 5=9.Please help me solve the exercise:
Find the error in the following argument, sqrt(x^2+1)=x+1 and so let x=2 sqrt(5)=9, therefore 5=9
Thanks in advance!!!