#### bushra1175

##### Junior Member

- Joined
- Jun 14, 2020

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- 58

I only have one assumption. It says P2 & P3 equals P4 & P5. I would assume this means both sides equal 50%. I can't make sense of the other points. Some hints would be much appreciated.

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- Thread starter bushra1175
- Start date

- Joined
- Jun 14, 2020

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- 58

I only have one assumption. It says P2 & P3 equals P4 & P5. I would assume this means both sides equal 50%. I can't make sense of the other points. Some hints would be much appreciated.

- Joined
- Mar 16, 2016

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- 3,133

For simplicity, I'd call them a,b,c,d,e, respectively.

To solve for 5 unknowns, you will need 5 equations.

Convert each statement into an equation.

"The ad generated a total of 50 million views in a single day" translates to a + b + c + d + e = 50 (million).

"P5 produced 40% less views than P4" translates to what?

Do the same for the other 3 statements.

Try to get 5 equations in total. Once you have 5 equations, you can solve them simultaneously. If you're not sure how, come back with your 5 equations and then we can guide you further.

BTW, your assumption is incorrect. If P2&P3 and P4&P5 are both 50%, that doesn't leave anything left for P1.

- Joined
- Jun 14, 2020

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Here are my 5 equations:

P5 = P4 - (P4*0.4)

P1 = (P2+P3)/2

P2 = P3 + (P3*1.2)

P2 + P3 = P4 + P5

When you say we need to solve the equations simultaneously, do you mean like this?:

www.bbc.co.uk

I feel like that would take long for a timed numerical reasoning test. I'm only allowed around 2 minutes per question sadly

- Joined
- Nov 12, 2017

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There's one more equation (you only show 4), which comes from the opening paragraph.

Here are my 5 equations:

P5 = P4 - (P4*0.4)

P1 = (P2+P3)/2

P2 = P3 + (P3*1.2)

P2 + P3 = P4 + P5

When you say we need to solve the equations simultaneously, do you mean like this?:

## Loading…

www.bbc.co.uk

I feel like that would take long for a timed numerical reasoning test. I'm only allowed around 2 minutes per question sadly

It doesn't take too long to solve this by standard methods such as those introduced in your reference, once you have some experience with them; and there are some shortcuts you can take if you think rather than follow a routine method strictly. Give it a try. (I'd start with some substitutions to eliminate a couple variables immediately.)

I will add that I used variables a, b, c, d, e, which are easier to write and think about; and I took them to be in millions.

- Joined
- Jun 14, 2020

- Messages
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I'll give it a go. I also would like to know if the process of simultaneous equations would need to be used for the below problem since there are many unknowns?There's one more equation (you only show 4), which comes from the opening paragraph.

It doesn't take too long to solve this by standard methods such as those introduced in your reference, once you have some experience with them; and there are some shortcuts you can take if you think rather than follow a routine method strictly. Give it a try. (I'd start with some substitutions to eliminate a couple variables immediately.)

I will add that I used variables a, b, c, d, e, which are easier to write and think about; and I took them to be in millions.

- Joined
- Nov 12, 2017

- Messages
- 12,937

Yes, this second problem can also be solved by a system of equations; and it's a little more work. There's an additional twist, in that there are only three equations for four unknowns. Fortunately, you are asked only for proportions; I would add in a fourth equation, A+B+C+D = 100, so that the four variables represent percentages of the total.I'll give it a go. I also would like to know if the process of simultaneous equations would need to be used for the below problem since there are many unknowns?

View attachment 29569

I don't see any better method.