F fish New member Joined Mar 21, 2016 Messages 1 Mar 21, 2016 #1 tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem.
tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem.
D Deleted member 4993 Guest Mar 21, 2016 #2 fish said: tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem. Click to expand... Let sin-1(-12/13) = Θ → sin(Θ) = - 12/13 → tan(Θ) = ? then tan(2Θ) = ?
fish said: tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem. Click to expand... Let sin-1(-12/13) = Θ → sin(Θ) = - 12/13 → tan(Θ) = ? then tan(2Θ) = ?
