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Help please with X / .3 = 4x + 6.28
- Thread starter Steven93
- Start date
Let's write this in fractions. I don't like decimals. Just a thing.
\(\displaystyle \L\\\frac{x}{\frac{3}{10}}=\frac{10x}{3}\)
and \(\displaystyle 6.28=\frac{157}{25}\)
So, we have \(\displaystyle \L\\\frac{10x}{3}=4x+\frac{157}{25}\)
Subtract 4x from both sides:
\(\displaystyle \L\\\frac{-2x}{3}=\frac{157}{25}\)
Now, can you solve for x?.
\(\displaystyle \L\\\frac{x}{\frac{3}{10}}=\frac{10x}{3}\)
and \(\displaystyle 6.28=\frac{157}{25}\)
So, we have \(\displaystyle \L\\\frac{10x}{3}=4x+\frac{157}{25}\)
Subtract 4x from both sides:
\(\displaystyle \L\\\frac{-2x}{3}=\frac{157}{25}\)
Now, can you solve for x?.
D
Deleted member 4993
Guest
Re: Help please.
Multiply by 0.3 - both sides - to get rid of fraction
X/.3=4x+6.28
0.3*(X/.3) = 0.3(4x+6.28)
x = 1.2 * x + 1.884
Now ontinue...
Another waySteven93 said:Alright there is this one problem I've been having a lot of trouble with
X/.3=4x+6.28
Work
X/.3=4x+6.28
-4x -4x
-3x/.3=6.28
Multiply by 0.3 - both sides - to get rid of fraction
X/.3=4x+6.28
0.3*(X/.3) = 0.3(4x+6.28)
x = 1.2 * x + 1.884
Now ontinue...