I will guess that you mean the following:
. . . . .x<sup>2</sup> - 9 < 6x
If so, then get the quadratic all together on one side:
. . . . .x<sup>2</sup> - 6x - 9 < 0
Find the zeroes of the associated equality, x<sup>2</sup> - 6x - 9 = 0. The quadratic will be either above the axis (positive) or below the axis (negative) everywhere it isn't zero. What intervals then do you have? And on which of these intervals is the quadratic above the axis?
Eliz.
P.S. To do "or equal to" on the inequalities, use the "underline" button to underline the inequality sign.