Mrspi said:
DanieldeLucena said:
[attachment=0:3p0139c1]1.JPG[/attachment:3p0139c1]
Hmmmm....what would happen if you SQUARED both sides of that equation?
Why don't you try that, and see if something useful emerges.
If you're still stuck, post again, showing us your efforts.
I was referring to the original equation:
(a[sup:3p0139c1]1/2[/sup:3p0139c1] + a[sup:3p0139c1]-1/2[/sup:3p0139c1])[sup:3p0139c1]2[/sup:3p0139c1] = (10/3)[sup:3p0139c1]2[/sup:3p0139c1]
On the left side, we'll need the pattern for squaring a binomial.
The pattern for squaring a binomial is this: (m + n)[sup:3p0139c1]2[/sup:3p0139c1] = m[sup:3p0139c1]2[/sup:3p0139c1] + 2 m n + n[sup:3p0139c1]2[/sup:3p0139c1]
replace "m" with a[sup:3p0139c1]1/2[/sup:3p0139c1]
replace "n" with a[sup:3p0139c1]-1/2[/sup:3p0139c1]
(a[sup:3p0139c1]1/2[/sup:3p0139c1] + a[sup:3p0139c1]-1/2[/sup:3p0139c1])[sup:3p0139c1]2[/sup:3p0139c1] = (a[sup:3p0139c1]1/2[/sup:3p0139c1])[sup:3p0139c1]2[/sup:3p0139c1] + 2*a[sup:3p0139c1]1/2[/sup:3p0139c1]*a[sup:3p0139c1]-1/2[/sup:3p0139c1] + (a[sup:3p0139c1]-1/2[/sup:3p0139c1])[sup:3p0139c1]2[/sup:3p0139c1]
Now you need to apply some of the rules for exponents....when you raise a power to a power, you MULTIPLY the exponents. When you multiply two powers of the same base, you ADD the exponents.
a[sup:3p0139c1](1/2)*2[/sup:3p0139c1] + 2*a[sup:3p0139c1]1/2 + (-1/2)[/sup:3p0139c1] + a[sup:3p0139c1](-1/2)*2[/sup:3p0139c1] = 100/9
See what you can do with that now....