M Miniputtz New member Joined Feb 27, 2006 Messages 6 Mar 26, 2007 #1 I need help with this problem. \(\displaystyle y'' + 6y' + 18y = 180\). I know how to solve the homogeneous part, I got \(\displaystyle e^{-3x}(C_1Cos(3x)+C_2Sin(3x))\). Is that right? But I don't know how to get \(\displaystyle Y_p\).
I need help with this problem. \(\displaystyle y'' + 6y' + 18y = 180\). I know how to solve the homogeneous part, I got \(\displaystyle e^{-3x}(C_1Cos(3x)+C_2Sin(3x))\). Is that right? But I don't know how to get \(\displaystyle Y_p\).
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Mar 27, 2007 #2 \(\displaystyle \L\\y=C_{1}e^{-3x}cos(3x)+C_{2}e^{-3x}sin(3x)+10\)
