HELP Solving Trigonometric Equation sin^2 theta cos^2 theta=0

[exploding_butterfly]

sin^2 theta cos^2 theta=0; 0 < or = theta < 2pi

 

[Steven G]

Did you try anything? If yes, then please tell us what you tried and where you feel that you are going wrong and someone will point you in the correct direction.

From what I see you have a product that equals 0. What can you say next?

 

[Deleted member 4993]

sin^2 theta cos^2 theta=0; 0 < or = theta < 2pi

One way:

sin^2 (Θ) * cos^2 (Θ) =0

[sin(Θ) * cos(Θ)]^2 = 0

sin(2*Θ) = 0 ...... continue....

 

[HallsofIvy]

Csine is not a "one-to-one" function- for any given y there exist an infinite number of x values such that cos(x)= y. You have found only one of them.