Hi, I'm having troubles calculating the next limit(it is a Rabbe's test for a series). Thanks!
S shahar1231 New member Joined Sep 26, 2020 Messages 1 Sep 26, 2020 #1 Hi, I'm having troubles calculating the next limit(it is a Rabbe's test for a series). Thanks! Attachments 1601118452433.png 24 KB · Views: 0
D Deleted member 4993 Guest Sep 26, 2020 #2 shahar1231 said: Hi, I'm having troubles calculating the next limit(it is a Rabbe's test for a series). View attachment 21879 Thanks! Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem.
shahar1231 said: Hi, I'm having troubles calculating the next limit(it is a Rabbe's test for a series). View attachment 21879 Thanks! Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem.
pka Elite Member Joined Jan 29, 2005 Messages 11,971 Sep 26, 2020 #3 I suggest that we rearrange the limit: \(\mathop {\lim }\limits_{n \to \infty } n\left( {1 - \frac{{{{\left( {1 + \frac{1}{{n + 1}}} \right)}^{{{(n + 1)}^2}}}}}{{e{{\left( {1 + \frac{1}{n}} \right)}^{{n^2}}}}}} \right) = \mathop {\lim }\limits_{n \to \infty } n\left( {1 + \frac{1}{e}{{\left( {1 + \frac{1}{n}} \right)}^{ - {n^2}}}{{\left( {1 + \frac{1}{{n + 1}}} \right)}^{{{(n + 1)}^2}}}} \right)\). Now what is \(\mathop {\lim }\limits_{n \to \infty } \frac{1}{e}\left[ {{{\left( {1 + \frac{1}{n}} \right)}^{ - {n^2}}}} \right] = \frac{1}{e}\mathop {\lim }\limits_{n \to \infty } {\left[ {{{\left( {1 + \frac{1}{n}} \right)}^n}} \right]^{ - n}} = ?\) SEE HERE
I suggest that we rearrange the limit: \(\mathop {\lim }\limits_{n \to \infty } n\left( {1 - \frac{{{{\left( {1 + \frac{1}{{n + 1}}} \right)}^{{{(n + 1)}^2}}}}}{{e{{\left( {1 + \frac{1}{n}} \right)}^{{n^2}}}}}} \right) = \mathop {\lim }\limits_{n \to \infty } n\left( {1 + \frac{1}{e}{{\left( {1 + \frac{1}{n}} \right)}^{ - {n^2}}}{{\left( {1 + \frac{1}{{n + 1}}} \right)}^{{{(n + 1)}^2}}}} \right)\). Now what is \(\mathop {\lim }\limits_{n \to \infty } \frac{1}{e}\left[ {{{\left( {1 + \frac{1}{n}} \right)}^{ - {n^2}}}} \right] = \frac{1}{e}\mathop {\lim }\limits_{n \to \infty } {\left[ {{{\left( {1 + \frac{1}{n}} \right)}^n}} \right]^{ - n}} = ?\) SEE HERE