J jconnors New member Joined Oct 12, 2010 Messages 8 Oct 12, 2010 #1 Here is the question; Find three consecutive odd integers whose sum is 86 more than the second integer. I have I=1st I+86=2nd and I can't figure out the what 3rd should be. If I can get this then I can finish the problem. Any help?
Here is the question; Find three consecutive odd integers whose sum is 86 more than the second integer. I have I=1st I+86=2nd and I can't figure out the what 3rd should be. If I can get this then I can finish the problem. Any help?
J jconnors New member Joined Oct 12, 2010 Messages 8 Oct 12, 2010 #2 I have been looking at this for a minute now and I'm now at this; I=1st I+2=2nd I+4=3rd so then I come to this I+I+4=86+I+2 However when I finish this out I don't think its correct. Am I on the right path?
I have been looking at this for a minute now and I'm now at this; I=1st I+2=2nd I+4=3rd so then I come to this I+I+4=86+I+2 However when I finish this out I don't think its correct. Am I on the right path?
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Oct 12, 2010 #3 Hello, jconnors! You're still misreding the problem . . . Find three consecutive odd integers whose sum is 86 more than the second integer. Click to expand... \(\displaystyle \text{Let: }\;\begin{Bmatrix}x &=& \text{1st odd integer} \\ x+2 &=& \text{2nd odd integer} \\ x+4 &=& \text{3rd odd integer} \end{Bmatrix}\) \(\displaystyle \text{The equation is: }\;\underbrace{x + (x+2) + (x+4)}_{\text{Their sum}} \;\underbrace{=}_{\text{is}}\;\underbrace{86\;\;+}_{\text{86 more than}}\; \underbrace{(x+2)}_{\text{2nd integer}}\)
Hello, jconnors! You're still misreding the problem . . . Find three consecutive odd integers whose sum is 86 more than the second integer. Click to expand... \(\displaystyle \text{Let: }\;\begin{Bmatrix}x &=& \text{1st odd integer} \\ x+2 &=& \text{2nd odd integer} \\ x+4 &=& \text{3rd odd integer} \end{Bmatrix}\) \(\displaystyle \text{The equation is: }\;\underbrace{x + (x+2) + (x+4)}_{\text{Their sum}} \;\underbrace{=}_{\text{is}}\;\underbrace{86\;\;+}_{\text{86 more than}}\; \underbrace{(x+2)}_{\text{2nd integer}}\)
J jconnors New member Joined Oct 12, 2010 Messages 8 Oct 12, 2010 #4 Thank you so much, I see where I went wrong.