Krahe
New member
- Joined
- Oct 2, 2016
- Messages
- 4
I'm taking Cal III, and it has been 3 years since I have taken the previous course so my skills are a little rusty. The equation is,
r(t)= (e^t) i +(2/9) e^(2t) j at t=ln3
The question wants this equation in terms of x and y and then evaluate the velocity and acceleration vectors and the given value of t. Finding v(t) and a(t) is easy, but I'm having trouble working with logs.
This is my thought process for tackling the problem;
The question wants this equation in terms of x and y. Since i is x and j is y; I would set x= e^t and y= (2/9) e^(2t).
[FONT=Roboto, arial, sans-serif]Solving for t from the x equation; Take the natural log of both sides. therefore t=ln(x)
[/FONT]plugging that into y
y= (2/9) e^(2(ln(x))).
I checked the solution Manual and the answer provided was that y= (2/9) x^2.
Where did I mess up? Any Help would be greatly appreciated.
r(t)= (e^t) i +(2/9) e^(2t) j at t=ln3
The question wants this equation in terms of x and y and then evaluate the velocity and acceleration vectors and the given value of t. Finding v(t) and a(t) is easy, but I'm having trouble working with logs.
This is my thought process for tackling the problem;
The question wants this equation in terms of x and y. Since i is x and j is y; I would set x= e^t and y= (2/9) e^(2t).
[FONT=Roboto, arial, sans-serif]Solving for t from the x equation; Take the natural log of both sides. therefore t=ln(x)
[/FONT]plugging that into y
y= (2/9) e^(2(ln(x))).
I checked the solution Manual and the answer provided was that y= (2/9) x^2.
Where did I mess up? Any Help would be greatly appreciated.