"Use the shell method to calculate the volume of rotation about the x‑axis for the area underneath the graph y=(x−4)^(1/3)−2 on [12, 31]."
First I rewrote the formula to x=(y+2)^3+4
Then I did the integral of 2pi(y)((y+2)^3+4) on [0, 1]
I got the answer (117pi)/5, but it's not correct. What did I do wrong?
First I rewrote the formula to x=(y+2)^3+4
Then I did the integral of 2pi(y)((y+2)^3+4) on [0, 1]
I got the answer (117pi)/5, but it's not correct. What did I do wrong?