HELP WITH SONS HOMEWORK! CHANCE TO CORRECT! pLEASE HELP

[kelly.a.miller1]

Think about rolling a die, then spinning a spinner with 4 A's, 3B's and two C's on it. What is the probability of rolling an even and then spinning a C? iTS A QUESTION ON MY SONS MATH PAPER. He is an eighth grader and we add 3*6 = 2/9 to get 13/18, but that was incorrect. Please help. How do you solve this?

 

[chrisr]

Any side of the 6 sides of the die can end up paired with any of the 9 options for the spinner.

That's 6(9)=54 possibilities.

There are 3 evens on the die and each of them can match with the two C's in 3(2)=6 ways.

So the probability is

\(\displaystyle \frac{6}{54}=\frac{1}{9}\)

Doing it your way, you should be multiplying the probabilities,
because it is an and situation not or.

 

[masters]

Think about rolling a die, then spinning a spinner with 4 A's, 3B's and two C's on it. What is the probability of rolling an even and then spinning a C? iTS A QUESTION ON MY SONS MATH PAPER. He is an eighth grader and we add 3*6 = 2/9 to get 13/18, but that was incorrect. Please help. How do you solve this?

Hi kelly.a.miller1,

When two events, A and B, are independent, the probability of both occurring is:
P(A and B) = P(A) · P(B).

So, the probability of tossing an even number on the die is 3/6 or 1/2.

The probability of landing on a C on the wheel is 2/9.

The probability of both events happening is 1/2 X 2/9 = 2/18 or 1/9.