I know the answer is 1/(s-6)^2. I know I am to integrate (e^(-st)*t*e^(6t)*dt) from 0 to infinity which is = integrate (e^((6-s)t)*t*dt) from 0 to infinity. I am certain that I am to use integration by parts with u = t, du = dt, dv = e^((6-s)t)*dt, and v = (this is where I am uncertain) 1/(6-s) *e((6-s)t). When I find v, do I still have to multiply by -1 because s = f(t) (chain rule)? Integrating this thing is not easy. Thank you for the help.