[MATH]c\log_a(b)=\log_a\left(b^c\right)[/MATH]
[MATH]\log_a(b)-\log_a(c)=\log_a\left(\frac{b}{c}\right)[/MATH]
How can you rewrite the LHS of the given equation?
[MATH]c\log_a(b)=\log_a\left(b^c\right)[/MATH]
[MATH]\log_a(b)-\log_a(c)=\log_a\left(\frac{b}{c}\right)[/MATH]
How can you rewrite the LHS of the given equation?
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