Help x-intercepts

yorkmanz

New member
1. What are the x-intercepts of y=(x−2)(x+5) ?

• A. (0, 2) and (0, -5)
• B. (0, -2) and (0, 5)
• C. (-2, 0) and (5, 0)
• D. (2, 0) and (-5, 0)

answer is D
X-2=>
X=2 (2,0)

X+5=0
X=-5 (-5,0)

Correct or not

1. Which of these quadratic functions has exactly one x -intercept?

• A. y=x 2 −9
• B. y=x 2 −6x+9
• C. y=x 2 −5x+6
• D. y=x 2 +x−6
MY ANSWER IS

A

(X-#)(X+3)

CORRECT OR NOT

1. Which of the following parabolas opens upward and appears narrower than y=−3x 2 +2x−1 ?

• A. y= 4x 2 −2x−1
• B. y= −4x 2 +2x−1
• C. y= x 2 +4x
D. y= −2x 2 +x+

MY ANSWER IS

A

CORRECT OR NOT

THANKS MUCH

Subhotosh Khan

Super Moderator
Staff member
1. What are the x-intercepts of y=(x−2)(x+5) ?

• A. (0, 2) and (0, -5)
• B. (0, -2) and (0, 5)
• C. (-2, 0) and (5, 0)
• D. (2, 0) and (-5, 0)

answer is D
X-2=>
X=2 (2,0)

X+5=0
X=-5 (-5,0)

Correct or not

1. Which of these quadratic functions has exactly one x -intercept?

• A. y=x 2 −9
• B. y=x 2 −6x+9
• C. y=x 2 −5x+6
• D. y=x 2 +x−6
MY ANSWER IS

A

(X-#)(X+3)

CORRECT OR NOT ...... Don't know - because the equations you posted above are not quadratic equations

1. Which of the following parabolas opens upward and appears narrower than y=−3x 2 +2x−1 ?

• A. y= 4x 2 −2x−1
• B. y= −4x 2 +2x−1
• C. y= x 2 +4x
D. y= −2x 2 +x+

MY ANSWER IS

A

CORRECT OR NOT..... Don't know - because the equations you posted above are not quadratic equations

THANKS MUCH
You are not posting correct problems.

As posted. you do not have a quadratic equation.

In your other post, I guessed the correct equation and posted it.

Now it is your turn - you will need to post correct problems.

Last edited:

yorkmanz

New member
You are not posting correct problems.

As posted. you do not have a quadratic equation.

In your other post, I guessed the correct equation and posted it.

Now it is your turn - you will need to post correct problems.

1. Which of these quadratic functions has exactly one x -intercept?

• A. y=x^2 −9
• B. y=x^2−6x+9
• C. y=x^2 −5x+6
• D. y=x^2 +x−6

MY ANSWER IS

A

CORRECT OR NOT ...... Don't know - because the equations you posted above are not quadratic equations

2. Which of the following parabolas opens upward and appears narrower than y=−3x 2 +2x−1 ?

• A. y= 4x^2 −2x−1
• B. y= −4x^2 +2x−1
• C. y= x^2 +4x
D. y= −2x^2 +x+

MY ANSWER IS

A

CORRECT OR NOT..... Don't know - because the equations you posted above are not quadratic equations

x^2 is quadric

THANKS

Subhotosh Khan

Super Moderator
Staff member
1. Which of these quadratic functions has exactly one x -intercept?

• A. y=x^2 −9
• B. y=x^2−6x+9
• C. y=x^2 −5x+6
• D. y=x^2 +x−6

MY ANSWER IS

A ............................ A has two x-intercepts x=3 and x=-3

CORRECT OR NOT ....Incorrect

2. Which of the following parabolas opens upward and appears narrower than y=−3x?2 +2x−1 ?.......?

• A. y= 4x^2 −2x−1
• B. y= −4x^2 +2x−1
• C. y= x^2 +4x
D. y= −2x^2 +x+ ? ............................................

MY ANSWER IS

A

CORRECT OR NOT..... Don't know

.

HallsofIvy

Elite Member
1. What are the x-intercepts of y=(x−2)(x+5) ?

• A. (0, 2) and (0, -5)
• B. (0, -2) and (0, 5)
• C. (-2, 0) and (5, 0)
• D. (2, 0) and (-5, 0)

answer is D
X-2=>
X=2 (2,0)

X+5=0
X=-5 (-5,0)

Correct or not
Yes, that is correct. An "x- intercept" is a point on the graph where the graph crosses ("intersects") the x-axis. There y= 0. If y= (x- 2)(x+ 5)= 0 then either x- 2= 0 or x+ 5= 0. If x- 2= 0 then x= 2. If x+ 5= 0 then x= -5. In either case y= 0 so the x-intercepts are (2, 0) and (-5, 0).

1. Which of these quadratic functions has exactly one x -intercept?

• A. y=x 2 −9
• B. y=x 2 −6x+9
• C. y=x 2 −5x+6
• D. y=x 2 +x−6
MY ANSWER IS

A

(X-#)(X+3)

CORRECT OR NOT
No, that is not correct
A. $$\displaystyle y= x^2- 9= (x- 3)(x+ 3)= 0$$. We have either x- 3= 0 so x= -3 or x+ 3= 0 so x= -3. The two x-intercepts are (3, 0) and (-3, 0).
B. $$\displaystyle y= x^2- 6x+ 9= (x- 3)^2= 0$$. We must have x= 3. There is only one x-intercept.
C. $$\displaystyle y= x^2- 5x+ 6= (x- 3)(x- 2)= 0$$. We must have either x- 3= 0 so x= 3 or x- 2= 0 so x= 2. The two x-intercepts are (3, 0) and (2, 0).
D. $$\displaystyle y= x^2+ x- 6= (x+ 3)(x- 2)= 0$$. We must have either x+ 3= 0 so x= -3 or x- 2= 0 so x= 2. The two x-intercepts are (-3, 0) and (2, 0).
The correct answer is B.

1. Which of the following parabolas opens upward and appears narrower than y=−3x 2 +2x−1 ?

• A. y= 4x 2 −2x−1
• B. y= −4x 2 +2x−1
• C. y= x 2 +4x
D. y= −2x 2 +x+

MY ANSWER IS

A

CORRECT OR NOT
Yes, that is correct.
A parabola opens upward if and only if its leading coefficient (the coefficient of $$\displaystyle x^2$$) is positive. That is true in A and C. How "narrow" a parabola appears depends upon how large the absolute value of the leading coefficient is. The larger the leading coefficient, the "narrower" the parabola is. |4|= 4 is larger than |-3|= 3 while |1|= 1 is not.

THANKS MUCH

Otis

Senior Member
… An "x- intercept" is a point on the graph where the graph crosses ("intersects") the x-axis …
Rather than using "crosses the axis" or "intersects the axis", I prefer a phrase like "crosses or just touches the axis".

The word "crosses" (in particular) can imply for beginning students that curves always continue on the other side of the axis, which we know is not always the case. :cool:

yorkmanz

New member
Yes, that is correct. An "x- intercept" is a point on the graph where the graph crosses ("intersects") the x-axis. There y= 0. If y= (x- 2)(x+ 5)= 0 then either x- 2= 0 or x+ 5= 0. If x- 2= 0 then x= 2. If x+ 5= 0 then x= -5. In either case y= 0 so the x-intercepts are (2, 0) and (-5, 0).

No, that is not correct
A. $$\displaystyle y= x^2- 9= (x- 3)(x+ 3)= 0$$. We have either x- 3= 0 so x= -3 or x+ 3= 0 so x= -3. The two x-intercepts are (3, 0) and (-3, 0).
B. $$\displaystyle y= x^2- 6x+ 9= (x- 3)^2= 0$$. We must have x= 3. There is only one x-intercept.
C. $$\displaystyle y= x^2- 5x+ 6= (x- 3)(x- 2)= 0$$. We must have either x- 3= 0 so x= 3 or x- 2= 0 so x= 2. The two x-intercepts are (3, 0) and (2, 0).
D. $$\displaystyle y= x^2+ x- 6= (x+ 3)(x- 2)= 0$$. We must have either x+ 3= 0 so x= -3 or x- 2= 0 so x= 2. The two x-intercepts are (-3, 0) and (2, 0).
The correct answer is B.

Yes, that is correct.
A parabola opens upward if and only if its leading coefficient (the coefficient of $$\displaystyle x^2$$) is positive. That is true in A and C. How "narrow" a parabola appears depends upon how large the absolute value of the leading coefficient is. The larger the leading coefficient, the "narrower" the parabola is. |4|= 4 is larger than |-3|= 3 while |1|= 1 is not.

Thank you man .. that's a perfect explanation...