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[swag312]

Productivity during the working day [MATH]0 \le t \le 8 [/MATH] shifted according to the law [MATH]5 - \frac{1}{4} \sqrt t[/MATH]. Calculate the job done in the first 4 hours of work.

 

[Romsek]

What are your initial thoughts on the problem. See the posting guidelines etc.

 

[swag312]

I'm kinda lost with this one. Puting 4 instead of [MATH]t[/MATH] would be too simple in my opinion.

 

[Romsek]

My immediate thought is that you need to integrate the productivity function from 0 to 4.
But you've posted this in the intermediate/advanced algebra forum.

I'm not sure how you would calculate the amount of the job done without calculus.
Have they given you a numerical answer?

 

[swag312]

Nope, maybe I posted it in a wrong section. Do you know how to solve this issue?

 

[Romsek]

Nope, maybe I posted it in a wrong section. Do you know how to solve this issue?

Do you know what integration is? I think what you are after is

\(\displaystyle job = \displaystyle \int_0^4 \left [5 - \dfrac 1 4 \sqrt{t}\right ]~dt\)

Does that mean anything to you?