- Thread starter Dominic
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12+3y=-2x

3y=-2x-12

y=(-2/3)x-4

If you compare that to y=mx+b, which term corresponds with m and which term corresponds with b?

G

Dominic, do you understand how to get an equation into the form y = mx + b now?

The equation was y=(-2/3)x-4 and now has the form y=mx+b.

No, but like tkhunny wrote, you are close. Remember, the form y=mx+b has a + between the mx and b. You should rewrite the equation so that there is a + between the mx and b, before reading off the value of b. We have:Dominic said:I think it's m is -2/3 and b is 4?

. . . . y = (-2/3)x - 4

which can be rewritten as:

. . . . y = (-2/3)x + (-4)

Now that we have a + between the mx and b, we can read off the value of b. So really, we actually have m = -2/3 and b = -4.

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so, would you do the parenthese first?

G

Depends on what you're trying to do. In this problem, we're not evaluating anything, so we don't evaluate anything in parentheses first. If you had a value for x, and you plugged it into (-2/3)x - 4 and wanted to evaluate that, then you would evaluate what's in parentheses first.so, would you do the parenthese first?

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wouldnt you use the formula x1/y1 x x2/yx for the slopne and intercept?

G

Do you mean x<sub>1</sub>/y<sub>1</sub> * x<sub>2</sub> / (y * x) ?

How would you use that?

How would you use that?

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to determine the slope.i guess theres different ways thats how it was done in my school.alexflury said:Do you mean x<sub>1</sub>/y<sub>1</sub> * x<sub>2</sub> / (y * x) ?

How would you use that?

G

I don't know how you would use x<sub>1</sub>/y<sub>1</sub> * x<sub>2</sub> / (y * x) to get the slope.