Here's a fun math/Zoom question for you all:

Z

ziggiesmalls

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Jan 13, 2021
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If I have 6 people in a group and each participant needs to meet each other in pairs of 2, how could I arrange Zoom Breakout rooms so that no one meets another twice? (3 Breakout rooms consisting of 2 people per session)
Here are the possible pairs I have (the letters represent initials of participants): K x R, K x J, K x C, K x N, K x Z, R x J, R x C, R x N, R x Z, J x C, J x N, J x Z, C x N, C x Z, N x Z
So with this in mind, it should break down into 5 total sessions with 3 breakout rooms in each session and 2 participants per breakout room. I just can't seem to figure out how to configure it without duplicate people being in a session.
 
I should follow our usual rules and ask you what method you've used to try to solve this, then give a hint. But I had too much fun quickly doing this with a little technology: I drew 6 points on a circle, and just drew 5 sets of 3 segments (each set a different color). It wasn't hard this way. Here is my result:
1610584652470.png
I can't guarantee that the same method would work for other numbers; it may well be impossible in some cases. But all I had to do was draw one line from A and find two other pairs that hadn't been used yet for the others.
 
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